PHYS 320 Week 2 iLab 2 (Devry)
Part 1
1. The measured resistance of the heater is 10.4W(1 point)
2. The voltage applied across the heating resistor is 5.9V (1 point)
3. The power dissipated by the heating resistor is 3.35W (1 point)
4. The mass of water in cup is 150 grams (1 point)
5. Paste a copy of your temperature–time graph here. (1 point)
6. Data Table (4 points)
Part 2
7. Use the data from Part 2 to complete the table below. (4 points)
8. The heat lost by the hot bolt is equal to the heat gained by the water in the calorimeter. Use the data provided in the table and what you know about heat to solve for the specific heat (CB) of the steel. Show your work. (4 points)
9. Look up the specific heat of carbon steel in your text or online. Find the percent difference between your calculated specific heat and the accepted value. Show your work. (4 points)
Questions
10. In Part 1, was the thermal energy gained by the water greater, the same as, or less than the electrical energy dissipated by the resistor? Explain. (2 points)
11. The heating resistor is rated at 10 ohms and 1 watt. What percentage of the power rating was used during this activity? Why didn’t the resistor burn up? (2 points)
12. What are some factors that could account for the percent difference between the experimental and the accepted values for the electrical equivalent of heat and for the specific heat of the steel bolt? (2 points)
13. Does the air inside the calorimeter also gain heat? Why do we exclude this from our calculation? (2 points)
No comments:
Post a Comment